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BEDMAS

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1

Overview

Achievement Criteria | Key Words
Review of basic number skills
Multiples, Factors & Prime numbers
Common factors & Common Multiples
Order of operations: BEDMAS
Calculator use with powers

Khan Video Tutorial: Finding Factors of a Number |
BEDMAS Video 1 | Video 2 NOTE (parentheses is the same as Brackets

Class notes, Blank BEDMAS notes |
Class notes, Blank Multiples primes notes

General Number problem

Factors p4, Ex 1.02,
Primes p5 Ex1.03
BEDMAS p7 Ex 1.04

NuLake p37, 38

 

 

 

When working with order of operations it is helpful to use mental reminders such as acronyms. One such reminder is BEDMAS.

 

This is the general order in which we perform operations. Keep in mind that M & D are done in the order in which they occur, (left to right) if they are the only two operations to consider. This is also true of A & S.
B
is for Brackets
E
is for Exponents
D
is for Division
M
is for Multiplication
A
is for Addition
S
is for Subtraction

 
BEDMAS
Example:
First do what is in Brackets, 4 - 1 = 3
2 + 3[ 5 + (4 - 1)2]
Next do the Exponent, 32 = 9
2 + 3[ 5 + (3)2]
Now you must do the next Bracket, 5+9 =14
2 + 3[ 5 + 9]
Multiplication is next, 3 x 14 = 42
2 + 3[ 14]
Last is the Addition, 2 + 42 = 44
2 + 42
Answer
44
   

 

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Bedmas Practice

Try these problems.
1.  20 + 3(5 - 1) =

2.  3 + 22(1+8) =

3.  (5 x 4 )2 =

4.  2( 3 + 5 ) - 9 =

5.  2[ 13 - ( 1+6)] =

6.  48 / 3 + 5 =

7.  3(6+4)(5 - 3) =

8.  100 - 4(7 - 4)3 =

9.  12 + 23 + 33 =

  (24 - 6)/2 = 
  

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More Practice of BEDMAS

B – Brackets – go from the INNERMOST brackets to the OUTERMOST
E – Exponents – can be written as the form 83 or 8^3
D – Division - In the order they occur
M – Multiplication - In the order they occur
A – Addition- In the order they occur
S – Subtraction - In the order they occur                      
 
e.g.  {3 + 4 [(5 x 6) / 5] – 3} + 4
= {3 + 4 [30/5] -3} + 4
= {3 + 4 [6] – 3} + 4
= {3 + 24 – 3} + 4
= {24} + 4
= 28
 
1.    (6)(3) + 7 – 10/2
2.    {45/5 (3) + [7 + 3(10)] – 4}
3.     14/7 – 2 x 62
4.     9 + (4)(3) / 6 - 2
5.    [ 30 + (3)(2) / 2 – 4]
6.    12 x 11 + 33 / 3
7.     { 48 + [ (16/4 x 3) + 2 – 5] + 3}
8.     13 - 23 + 6/3
 
Solutions:
1. = 18 + 7 – 5  2.   = {9 x 3 + [7 + 30] - 4} 3.  = 2 – (2 x 36)   
     = 25 - 5      = 27 + 37 – 4        = 2 – 72  
     = 20      = 67 – 4           = -70    
       = 63  
     
4. = 9 + (18 ÷ 6) - 2 5.  = [30 + 6/2 – 4]   6.  =121 + 9/3  
      = 9 + (3) - 2      = [30 + 3 – 4]      = 121 + 3
      = 10      = [33-4]        = 124 
       = 29  
     
7.  = {48 + [(4 x 3) + 2 – 5] + 3} 8.  = 13 – 8 + 2  
     = {48 + [12 + 2 – 5] + 3}      = 7  
     = {48 + [9] + 3}    
     = 60     

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